A transmission line is drawn as two black wires. At a distance x into the line, there is current phasor I(x) traveling through each wire, and there is a voltage difference phasor V(x) between the wires (bottom voltage minus top voltage). If
Y
0
{\displaystyle Y_{0}}
is the characteristic admittance of the line, then
I
(
x
)
/
V
(
x
)
=
Y
0
{\displaystyle I(x)/V(x)=Y_{0}}
for a wave moving rightward, or
I
(
x
)
/
V
(
x
)
=
−
Y
0
{\displaystyle I(x)/V(x)=-Y_{0}}
for a wave moving leftward.
Characteristic admittance is the mathematical inverse of the characteristic impedance .
The general expression for the characteristic admittance of a transmission line is:
Y
0
=
G
+
j
ω
C
R
+
j
ω
L
{\displaystyle Y_{0}={\sqrt {\frac {G+j\omega C}{R+j\omega L}}}}
where
R
{\displaystyle R}
is the resistance per unit length,
L
{\displaystyle L}
is the inductance per unit length,
G
{\displaystyle G}
is the conductance of the dielectric per unit length,
C
{\displaystyle C}
is the capacitance per unit length,
j
{\displaystyle j}
is the imaginary unit , and
ω
{\displaystyle \omega }
is the angular frequency .
The current and voltage phasors on the line are related by the characteristic admittance as:
I
+
V
+
=
Y
0
=
−
I
−
V
−
{\displaystyle {\frac {I^{+}}{V^{+}}}=Y_{0}=-{\frac {I^{-}}{V^{-}}}}
where the superscripts
+
{\displaystyle +}
and
−
{\displaystyle -}
represent forward- and backward-traveling waves, respectively.
See also
References
Categories :
Characteristic admittance
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